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NEW QUESTION 26
Which of the following code blocks returns all unique values across all values in columns value and productId in DataFrame transactionsDf in a one-column DataFrame?
  • A. tranactionsDf.select('value').join(transactionsDf.select('productId'), col('value')==col('productId'),
    'outer')
  • B. transactionsDf.select('value').union(transactionsDf.select('productId')).distinct()
  • C. transactionsDf.select(col('value'), col('productId')).agg({'*': 'count'})
  • D. transactionsDf.select('value', 'productId').distinct()
  • E. transactionsDf.agg({'value': 'collect_set', 'productId': 'collect_set'})
Answer: B
Explanation:
Explanation
transactionsDf.select('value').union(transactionsDf.select('productId')).distinct() Correct. This code block uses a common pattern for finding the unique values across multiple columns: union and distinct. In fact, it is so common that it is even mentioned in the Spark documentation for the union command (link below).
transactionsDf.select('value', 'productId').distinct()
Wrong. This code block returns unique rows, but not unique values.
transactionsDf.agg({'value': 'collect_set', 'productId': 'collect_set'}) Incorrect. This code block will output a one-row, two-column DataFrame where each cell has an array of unique values in the respective column (even omitting any nulls).
transactionsDf.select(col('value'), col('productId')).agg({'*': 'count'}) No. This command will count the number of rows, but will not return unique values.
transactionsDf.select('value').join(transactionsDf.select('productId'), col('value')==col('productId'), 'outer') Wrong. This command will perform an outer join of the value and productId columns. As such, it will return a two-column DataFrame. If you picked this answer, it might be a good idea for you to read up on the difference between union and join, a link is posted below.
More info: pyspark.sql.DataFrame.union - PySpark 3.1.2 documentation, sql - What is the difference between JOIN and UNION? - Stack Overflow Static notebook | Dynamic notebook: See test 3

NEW QUESTION 27
The code block shown below should return a copy of DataFrame transactionsDf without columns value and productId and with an additional column associateId that has the value 5. Choose the answer that correctly fills the blanks in the code block to accomplish this.
transactionsDf.__1__(__2__, __3__).__4__(__5__, 'value')
  • A. 1. withColumn
    2. col(associateId)
    3. lit(5)
    4. drop
    5. col(productId)
  • B. 1. withNewColumn
    2. associateId
    3. lit(5)
    4. drop
    5. productId
  • C. 1. withColumnRenamed
    2. 'associateId'
    3. 5
    4. drop
    5. 'productId'
  • D. 1. withColumn
    2. 'associateId'
    3. lit(5)
    4. drop
    5. 'productId'
  • E. 1. withColumn
    2. 'associateId'
    3. 5
    4. remove
    5. 'productId'
Answer: D
Explanation:
Explanation
Correct code block:
transactionsDf.withColumn('associateId', lit(5)).drop('productId', 'value') For solving this question it is important that you know the lit() function (link to documentation below). This function enables you to add a column of a constant value to a DataFrame.
More info: pyspark.sql.functions.lit - PySpark 3.1.1 documentation
Static notebook | Dynamic notebook: See test 1

NEW QUESTION 28
Which of the following statements about DAGs is correct?
  • A. DAGs can be decomposed into tasks that are executed in parallel.
  • B. Spark strategically hides DAGs from developers, since the high degree of automation in Spark means that developers never need to consider DAG layouts.
  • C. DAGs help direct how Spark executors process tasks, but are a limitation to the proper execution of a query when an executor fails.
  • D. In contrast to transformations, DAGs are never lazily executed.
  • E. DAG stands for "Directing Acyclic Graph".
Answer: A
Explanation:
Explanation
DAG stands for "Directing Acyclic Graph".
No, DAG stands for "Directed Acyclic Graph".
Spark strategically hides DAGs from developers, since the high degree of automation in Spark means that developers never need to consider DAG layouts.
No, quite the opposite. You can access DAGs through the Spark UI and they can be of great help when optimizing queries manually.
In contrast to transformations, DAGs are never lazily executed.
DAGs represent the execution plan in Spark and as such are lazily executed when the driver requests the data processed in the DAG.

NEW QUESTION 29
Which of the following code blocks returns the number of unique values in column storeId of DataFrame transactionsDf?
  • A. transactionsDf.distinct().select("storeId").count()
  • B. transactionsDf.select(count("storeId")).dropDuplicates()
  • C. transactionsDf.select(distinct("storeId")).count()
  • D. transactionsDf.dropDuplicates().agg(count("storeId"))
  • E. transactionsDf.select("storeId").dropDuplicates().count()
Answer: E
Explanation:
Explanation
transactionsDf.select("storeId").dropDuplicates().count()
Correct! After dropping all duplicates from column storeId, the remaining rows get counted, representing the number of unique values in the column.
transactionsDf.select(count("storeId")).dropDuplicates()
No. transactionsDf.select(count("storeId")) just returns a single-row DataFrame showing the number of non-null rows. dropDuplicates() does not have any effect in this context.
transactionsDf.dropDuplicates().agg(count("storeId"))
Incorrect. While transactionsDf.dropDuplicates() removes duplicate rows from transactionsDf, it does not do so taking only column storeId into consideration, but eliminates full row duplicates instead.
transactionsDf.distinct().select("storeId").count()
Wrong. transactionsDf.distinct() identifies unique rows across all columns, but not only unique rows with respect to column storeId. This may leave duplicate values in the column, making the count not represent the number of unique values in that column.
transactionsDf.select(distinct("storeId")).count()
False. There is no distinct method in pyspark.sql.functions.

NEW QUESTION 30
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